What I also don't understand is that Cromer says nothing changes mathematically to win the MAC because win percentage takes precedence. If you have a team at 4-1 and another at 5-1 at the top of the division, and the 5-1 team's loss is to the former, who goes to the championship? Win percentage favors the 5-1 team.
The MAC kind of worded it that way before previously too, which was confusing, but it also said if teams have the same number of losses that head to head would be the first tiebreaker. So based on how people have discussed it, I think a 4-1 team would win over a 5-1 team if it had the head-to-head win.
I reached out to a couple MAC contacts and have a little more clarity on the matter. Here's what was shared with me:
Win percentage will be the No. 1 determining factor in ranking teams (hold on, there's a twist). For example, a 5-0 team would obviously have a better win percentage than a 5-1 team, so it would get the edge in that case. HOWEVER - if two teams have the same number of losses, but have different win totals (for example, one team is 5-1 and the other is 4-1), then the head to head result of those two teams would then take precedent. After that, a normal tiebreaker process would begin where you start going back through the rankings and compare what the teams did against that team.
With that said, Ohio is still clearly in control of its own destiny then. For example let's say Ohio and Buffalo are the top two in the East, and Ohio wins out to finish 4-1 and Buffalo finishes 5-1. Then Ohio would go to the MACC because despite Buffalo having the better win percentage, since both teams have the same number of losses, Ohio would get the edge because it beat UB head to head.
Last Edited: 11/18/2020 10:53:46 PM by OhioBobcat