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Topic: Mathematics of Unbeaten Season
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L.C.
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LC
Member Since: 9/1/2005
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L.C.
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Posted: 10/16/2012 5:44 PM
L.C. wrote:expand_more
...
@Miami 70%
EMU 90%
BGSU 80%
@Ball State 70%
@Kent 65%

Add that up, there is a 7.5% chance of going undefeated. There is also a 20% chance of losing only 1 game. ...

Revisiting these odds, and re-assessing the chances of winning each game in light of how the team has been playing, I now have:
@Miami 70% (unchanged)
EMU 90% (unchanged)
BGSU 70% (was 80%)
@Ball State 50% (was 70%)
@Kent 48% (was 65%)

That gives a chance of going 12-0 of 11%, and a chance of going 13-1 of 32%. There is still a 57% chance of two or more losses. They have to win them one game at a time, and keep avoiding the ditch. With the #25 rank, the eyepatch is all the more obvious, and the desire to beat the Bobcats that much higher.
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