Could find anything official form the MAC but, I did find this in an article from the Toledo blade (
LINK) just before last years tourney (3/9/2013). It says division record is only used to determine the division champ.
Here is how the MAC breaks ties …
1. Between TWO teams:
A. Head-to-head competition
B. Division Record (10 games)^
C. Winning percentage* vs. ranked conference teams (top to bottom, regardless of division, vs.
common opponents regardless of the number of times played)
D. Coin flip
^ - For the purpose of determining the Division champion only
* - Winning percentage is used instead of record because of situations where teams do not play each other the same number of times. Therefore, a team that is 1-0 (1.000) would win the tiebreaker over a team that is 2-1 (.667).
2. For MULTIPLE (3 or more) team ties:
E. Total won-lost record of games played among the tied teams
F. Two (2)-team tie-breaker procedure goes into effect (refer to A)
NOTE: Once a three-team tie has been reduced to two teams, the two-team tiebreaker will go into effect
As far as a tie with Akron goes, they also lost to WMU, so it would be a push. Our 1-1 record against Toledo (vs. their 0-1) would give us the tie breaker.
Oh, I see. So our 0-2 against WMU is not worse than Akron's 0-1 because both are .000. If Buffalo passes Toledo in the standings, at worst, it will be a wash if Akron and Ohio are 1-1 against Buffalo. Our 1-1 against Toledo is clearly better than their 0-1, and it is looking more and more clear that neither Akron or Ohio are going to catch the top 3. Buffalo @ Akron is an important game for our bye prospects. One Akron loss plus us going at least 2-1 in our remaining games gives us a bye. Against the Eastern division, we are 4-3 while Akron is 3-4. Win out and we have a bye.
Last Edited: 2/27/2014 9:08:34 AM by shabamon